Ace Combat 04 was great.

CS major here, I would be happy to help you out. Reference 1: http://teamfortress.tv/forum/thread/1698/1#post-20551

Additional references available on request.

Bike ride, challenge myself to climb a mountain. The feeling when you crest the top is amazing.

It's good to know that with the high school soap opera genre dwindling, stultus is here to compensate with his episodic antics.

quash

Let
A = (x^10 + 3x^9)^(1/10) - x

Turn this into a fraction
A = [x(x^10 + 3x^9)^(1/10) - x^2] / [x]

Limit of this as x goes to infinity is undefined, so use L'Hopital. If you're unfamiliar, it basically says if the limit of some fraction is undefined, take the derivative of the top and bottom instead
lim A = lim [x(x^10 + 3x^9)^(1/10) + (1/10)(x)(x^10 + 3x^9)^(-9/10)(10x^9 + 27x^8) - 2x] / [1]

Just rearranging some stuff
lim A = lim x(x^10 + 3x^9)^(1/10) - x + (1/10)(x)(x^10 + 3x^9)^(-9/10)(10x^9 + 27x^8) - x

AHA
lim A = lim A + (1/10)(x)(x^10 + 3x^9)^(-9/10)(10x^9 + 27x^8) - x

Get rid of those As
lim 0 = lim (1/10)(x)(x^10 + 3x^9)^(-9/10)(10x^9 + 27x^8) - x
lim x = lim (1/10)(x)(x^10 + 3x^9)^(-9/10)(10x^9 + 27x^8)
lim 10 = lim (x^10 + 3x^9)^(-9/10)(10x^9 + 27x^8)

Uhhh let's multiply by (x^10 + 3x^9)/(10x^9 + 27x^8) on both sides and see what happens
lim 10(x^10 + 3x^9)/(10x^9 + 27x^8) = lim (x^10 + 3x^9)^(1/10)

Subtract x
lim 10(x^10 + 3x^9)/(10x^9 + 27x^8) - x = lim (x^10 + 3x^9)^(1/10) - x

WUT
lim 10(x^10 + 3x^9)/(10x^9 + 27x^8) - x = lim A
lim 10x^10/(10x^9 + 27x^8) + 3x^9/(10x^9 + 27x^8) - x = lim A

Pretty easy to simplify
lim x + 3/10 - x = lim A
lim A = lim 3/10