Water found to be wet
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SteamID3 | [U:1:81582491] |
SteamID32 | STEAM_0:1:40791245 |
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Different models of CPU have different voltage tolerances so I can't really say what's a safe voltage in your cpu. But generally..
Looking at specific clocks, recommendations are hard to gauge since few people actually want to spend money on testing what exact voltage destroys a cpu. Often people recommend lower voltages than what are actually still safe because they only know that "this voltage is safe" based on their own experience.
On the flip side, here isn't a cutoff between no damage and an insta-fried CPU, it's a sliding scale of how much degradation happens.
With a borderline voltage, the CPU may degrade slowly, causing the maximum stable clocks to decrease a few hours/days/weeks/months down the line. If you're planning on replacing the CPU in 1-2 years anyways you can afford to push a bit higher than if you want the CPU to last forever. (and If you're fine with trying to balance the risk of a slightly slower cpu with the opportunity of a slightly faster cpu.. generally though, fiddling with overclocks to get the absolute maximum out is just a hobby/another way to waste your time with your computer. You won't actually notice 3% more or less performance when you use a computer)
Temperatures also have an effect on stable clocks (and higher clocks cause a somewhat higher heat output even on the same voltage). Also, chips all have some defects, and how many defects yours has affects the maximum overclocks.
Because the damage potential increases exponentially with voltage, going 0.03V lower than a voltage that causes no damage in 1 year should pretty much never cause any damage (assuming relatively similar temperatures.) An unoverclocked CPU will usually last a decade of 24/7 stress testing (likely far longer than many other components of your pc)
idk those kinda looks like small trees to me
sniffgeogebra is taking our jobs
edit: wait i think thats desmos
its both
toads_tfnegative area square?
negative area makes sense if you consider it as the "area under a function" (so a defined integral of a function)
and you could just handwave it anyways.
This looks like a "find the overlapping area of three circles" question. It's extremely tedious, but pretty braindead with a symbolic calculator
Here's a very rough outline of how to find A3 (not wasting any more time on this):
https://i.imgur.com/2GSGwQ1.png
I guessed that the vague curves are sections of circle with center at a corner of the large square and radius the same as the square's side length
https://i.imgur.com/qny2VWS.png
the program gives the equations for the circles easily
https://i.imgur.com/mzP36RE.png
change the relevant half of the circle into a y=f(x) format
https://i.imgur.com/y15qo1k.png
https://i.imgur.com/53bLMWX.png
find the intersections of the relevant curves, and use them as the bounds of the defined integrals..
https://i.imgur.com/VqDoIGT.png
and just smack the integrals into a calculator, and you add them all together:
+ integral_(3/8 - sqrt(7)/8)^(1 - sqrt(3)/2) (sqrt(2 x - x^2) dx
- integral_(3/8 - sqrt(7)/8)^(1 - sqrt(3)/2) (sqrt(2 x - x^2) + 1/2 (-1 + 2 sqrt(x - x^2))) dx
+ integral_(1 - sqrt(3)/2)^(5/8 - sqrt(7)/8) 1/2 (1 - 2 sqrt(x - x^2)) dx
- integral_(1 - sqrt(3)/2)^(5/8 - sqrt(7)/8) 1/2 (1 - 2 sqrt(x - x^2)) dx
+ integral_(5/8 - sqrt(7)/8)^(1/2) (1 - sqrt(2 x - x^2)) dx
- integral_(5/8 - sqrt(7)/8)^(1/2) (1 - sqrt(1 - x^2)) dx
and multiply the result by the side length
and the final answer for A3 (unless I made mistakes....)
surprise, it's a massive clusterfuck:
(-47)*(9/64 - sqrt(3)/8 - (5 π)/12 + tan^(-1)(4 + sqrt(7)) + 1/64 (-17 + 16 sqrt(3) - 4 sqrt(7) - 8 sqrt(14 sqrt(3) - 24) - 16 sin^(-1)(3^(1/4)/sqrt(2)) + 16 csc^(-1)((2 sqrt(5 - sqrt(7)))/3)) + (1/64 (sqrt(321 + 48 sqrt(7) - 48 sqrt(43 + 16 sqrt(7))) + 8 (-3 + 4 sqrt(3) - sqrt(7) + 8 cot^(-1)(3/sqrt(31 + 8 sqrt(7))))) - (5 π)/12) - (1/64 (-9 + 16 sqrt(3) - 4 sqrt(7) - 8 sqrt(14 sqrt(3) - 24) - 16 sin^(-1)(3^(1/4)/sqrt(2)) + 16 csc^(-1)(2 sqrt(3 - sqrt(7))))) + (-1/64 sqrt(321 + 48 sqrt(7) - 48 sqrt(43 + 16 sqrt(7))) + π/3 + 1/8 (-1 + sqrt(7) - 8 cot^(-1)(3/sqrt(31 + 8 sqrt(7))))) - (1/192 (3 - 24 sqrt(3) + 24 sqrt(7) + 32 π - 96 cos^(-1)(1/8 (5 - sqrt(7))))))
= ~0.036566432691702221271670 - 0.019630731925696712432468 + 0.061918112844524846486709 - 0.0150274870976263361702352 + 0.04230790314076436373846 - 0.0173897792991522791591702
= 0.0887444503545161037349656 * (-47)
= ~-4.1709891666622568755433832..
and then just do that two more times for the final answer. It's not going to get much shorter.
Of course the question is pretty vague so this could be the solution to the wrong problem.
Matthesits me!! im telling you to shut the fuck up!!!
11 hours ago
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There just won't be a central currency.. they keys that already exist will prob increase in value so it won't make traders quit
Wait winger fires slower than pistol? What??
Maybe it's the same thing as this?
Apparently it's bad enough that my browser thinks it's better that I just see a black screen
jimmijwhat about smokking dick
As long as it's not your own dick it's fine