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SteamID64 76561198041848219
SteamID3 [U:1:81582491]
SteamID32 STEAM_0:1:40791245
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Signed Up August 2, 2016
Last Posted February 5, 2020 at 9:11 PM
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#3 trump acquitted in World Events

Water found to be wet

posted 2 weeks ago
#2 germs People in Off Topic

Using tftv

posted 3 weeks ago
#2 CPU Voltage in Hardware

Different models of CPU have different voltage tolerances so I can't really say what's a safe voltage in your cpu. But generally..

Looking at specific clocks, recommendations are hard to gauge since few people actually want to spend money on testing what exact voltage destroys a cpu. Often people recommend lower voltages than what are actually still safe because they only know that "this voltage is safe" based on their own experience.

On the flip side, here isn't a cutoff between no damage and an insta-fried CPU, it's a sliding scale of how much degradation happens.
With a borderline voltage, the CPU may degrade slowly, causing the maximum stable clocks to decrease a few hours/days/weeks/months down the line. If you're planning on replacing the CPU in 1-2 years anyways you can afford to push a bit higher than if you want the CPU to last forever. (and If you're fine with trying to balance the risk of a slightly slower cpu with the opportunity of a slightly faster cpu.. generally though, fiddling with overclocks to get the absolute maximum out is just a hobby/another way to waste your time with your computer. You won't actually notice 3% more or less performance when you use a computer)

Temperatures also have an effect on stable clocks (and higher clocks cause a somewhat higher heat output even on the same voltage). Also, chips all have some defects, and how many defects yours has affects the maximum overclocks.

Because the damage potential increases exponentially with voltage, going 0.03V lower than a voltage that causes no damage in 1 year should pretty much never cause any damage (assuming relatively similar temperatures.) An unoverclocked CPU will usually last a decade of 24/7 stress testing (likely far longer than many other components of your pc)

posted 1 month ago
#5 hey guys where do pineapples grow? in The Dumpster

idk those kinda looks like small trees to me

posted 1 month ago
#3 Enough is enough. It's 2020 now. in The Dumpster


posted 1 month ago
#27 Math problem IQ test in Off Topic
sniffgeogebra is taking our jobs
edit: wait i think thats desmos

its both

posted 2 months ago
#25 Math problem IQ test in Off Topic
toads_tfnegative area square?

negative area makes sense if you consider it as the "area under a function" (so a defined integral of a function)
and you could just handwave it anyways.

This looks like a "find the overlapping area of three circles" question. It's extremely tedious, but pretty braindead with a symbolic calculator

Here's a very rough outline of how to find A3 (not wasting any more time on this):

Show Content
let's start with an A_s (assuming it's the outer square) of 1 and multiply by the actual A_s at the very end
I guessed that the vague curves are sections of circle with center at a corner of the large square and radius the same as the square's side length
the program gives the equations for the circles easily
change the relevant half of the circle into a y=f(x) format
find the intersections of the relevant curves, and use them as the bounds of the defined integrals..
and just smack the integrals into a calculator, and you add them all together:

+ integral_(3/8 - sqrt(7)/8)^(1 - sqrt(3)/2) (sqrt(2 x - x^2) dx

- integral_(3/8 - sqrt(7)/8)^(1 - sqrt(3)/2) (sqrt(2 x - x^2) + 1/2 (-1 + 2 sqrt(x - x^2))) dx

+ integral_(1 - sqrt(3)/2)^(5/8 - sqrt(7)/8) 1/2 (1 - 2 sqrt(x - x^2)) dx

- integral_(1 - sqrt(3)/2)^(5/8 - sqrt(7)/8) 1/2 (1 - 2 sqrt(x - x^2)) dx

+ integral_(5/8 - sqrt(7)/8)^(1/2) (1 - sqrt(2 x - x^2)) dx

- integral_(5/8 - sqrt(7)/8)^(1/2) (1 - sqrt(1 - x^2)) dx
and multiply the result by the side length
and the final answer for A3 (unless I made mistakes....)

surprise, it's a massive clusterfuck:
(-47)*(9/64 - sqrt(3)/8 - (5 π)/12 + tan^(-1)(4 + sqrt(7)) + 1/64 (-17 + 16 sqrt(3) - 4 sqrt(7) - 8 sqrt(14 sqrt(3) - 24) - 16 sin^(-1)(3^(1/4)/sqrt(2)) + 16 csc^(-1)((2 sqrt(5 - sqrt(7)))/3)) + (1/64 (sqrt(321 + 48 sqrt(7) - 48 sqrt(43 + 16 sqrt(7))) + 8 (-3 + 4 sqrt(3) - sqrt(7) + 8 cot^(-1)(3/sqrt(31 + 8 sqrt(7))))) - (5 π)/12) - (1/64 (-9 + 16 sqrt(3) - 4 sqrt(7) - 8 sqrt(14 sqrt(3) - 24) - 16 sin^(-1)(3^(1/4)/sqrt(2)) + 16 csc^(-1)(2 sqrt(3 - sqrt(7))))) + (-1/64 sqrt(321 + 48 sqrt(7) - 48 sqrt(43 + 16 sqrt(7))) + π/3 + 1/8 (-1 + sqrt(7) - 8 cot^(-1)(3/sqrt(31 + 8 sqrt(7))))) - (1/192 (3 - 24 sqrt(3) + 24 sqrt(7) + 32 π - 96 cos^(-1)(1/8 (5 - sqrt(7))))))

= ~0.036566432691702221271670 - 0.019630731925696712432468 + 0.061918112844524846486709 - 0.0150274870976263361702352 + 0.04230790314076436373846 - 0.0173897792991522791591702

= 0.0887444503545161037349656 * (-47)
= ~-4.1709891666622568755433832..

and then just do that two more times for the final answer. It's not going to get much shorter.
Of course the question is pretty vague so this could be the solution to the wrong problem.
posted 2 months ago
#8 delet this in TF2 General Discussion



posted 2 months ago
#39 "who are you?" in TF2 General Discussion
Matthesits me!! im telling you to shut the fuck up!!!

11 hours ago
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posted 3 months ago
#24 MGE gods in TF2 General Discussion


posted 3 months ago
#2 CSGO Key Change in CSGO General Discussion

There just won't be a central currency.. they keys that already exist will prob increase in value so it won't make traders quit

posted 3 months ago
#5 Find your preferred damage-batching interval in TF2 General Discussion

Wait winger fires slower than pistol? What??

posted 4 months ago
#3 issue with your computer is blocking the vac syste in TF2 General Discussion

Maybe it's the same thing as this?


posted 5 months ago
#8 new thrasher merch in Music, Movies, TV

Apparently it's bad enough that my browser thinks it's better that I just see a black screen

posted 5 months ago
#13 what's a worse addiction to have? in Off Topic
jimmijwhat about smokking dick

As long as it's not your own dick it's fine

posted 7 months ago
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