rocketslay
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SteamID3 [U:1:116181125]
SteamID32 STEAM_0:1:58090562
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Signed Up June 24, 2016
Last Posted November 20, 2019 at 7:01 PM
Posts 1226 (0.4 per day)
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#8 Has this community become completely retarded? in TF2 General Discussion

why are people donating to send people to video game lans when u could be helpin to fight zika

x3people give money to what they want
chill out
posted about 7 years ago
#25 Valve limiting coaches in CS in CSGO General Discussion
dangomustardoverlordevery major team can easily afford oneAnd what about all the teams that can't afford one (or one worth having)?

if u can't afford a coach then it's highly unlikely u have players good enough to compete with top teams in the first place
also watchin 5 fraggers is more exciting for the average viewer tbh

posted about 7 years ago
#17 Valve limiting coaches in CS in CSGO General Discussion

lots of pros are really mad about this, and i can't really blame them.
https://www.reddit.com/r/GlobalOffensive/comments/4y6oah/prospersonalitys_reactions_to_the_new_coach_rule/

posted about 7 years ago
#7 Valve limiting coaches in CS in CSGO General Discussion

of all the things to fix... lol valve

posted about 7 years ago
#20 ESEA S22 Playoffs: froyotech vs. RONIN in Matches

why force a nature? is yomps quitting too?

posted about 7 years ago
#52 TF2 update for 8/16/16 (8/17/16 UTC) in TF2 General Discussion

tagg, man of his word SeemsGood

posted about 7 years ago
#16 forums where i can for ask help with math? in Off Topic

i don't want hats, it's no problem man :)

posted about 7 years ago
#13 forums where i can for ask help with math? in Off Topic

#2:
If n is prime, then for all numbers 1, 2, 3, ..., n-1, gcd(x,n) = 1, which follows from the definition of a prime number, so A(n) = n-1.
If n isn't prime, then for some number in 2, 3, ..., n-1, that number divides n, so A(n) < n-1.
#3:
If p is not a divisor of m, then p and m share no common factors, i.e. gcd(p, m) = 1. Therefore gcd(p^k, m) = 1.
If p divides m, clearly gcd(m, p^k) > 1.
#4: We want the number of integers between 1 and p^n that have no common factors with p^n. From #3, we know that unless x is a multiple of p, gcd(x, p^n) = 1. So we calculate the number of multiples of p between 1 and p^n, which is just p^(n-1). And the total number of integers between 1 and p^n is p^n, so the answer is A(p^n) = p^n - p^(n-1).

posted about 7 years ago
#12 forums where i can for ask help with math? in Off Topic

that is the euler totient function...
i'll try to answer your questions later :)

posted about 7 years ago
#1078 /r/tf2 posts that make you cringe in The Dumpster
theoxandmoonOh fuck

https://www.reddit.com/r/tf2/comments/4xynno/slug/d6jhzj2

lmfao

posted about 7 years ago
#1072 /r/tf2 posts that make you cringe in The Dumpster

"shut up and enjoy your memes"

that's like the first actual cringe i've seen in a while

posted about 7 years ago
#5 Interested in getting back into comp.. in TF2 General Discussion

https://www.youtube.com/watch?v=lDK9QqIzhwk

posted about 7 years ago
#49 The future of tf2 and i58 in The Dumpster

why does jill respond to r/tf2 more than tftv smh

posted about 7 years ago
#29 The future of tf2 and i58 in The Dumpster

Fuck you valve i wanna keep watching competitive tf2 stop killing it

posted about 7 years ago
#25 is it ever justified to murder an innocent? in The Dumpster

would you murder someone to make tf2 a big esport???

posted about 7 years ago
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