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statistics help
posted in Off Topic
1
#1
0 Frags +

got some stat homework due tonight, idk how to do some of em and i cant find shit on google
they seem pretty easy and kind of fun if you know what youre doing and like this stuff (like odds related to decks of cards) so if anyone wants to help a boy out add me on steam http://steamcommunity.com/id/alec___/

got some stat homework due tonight, idk how to do some of em and i cant find shit on google
they seem pretty easy and kind of fun if you know what youre doing and like this stuff (like odds related to decks of cards) so if anyone wants to help a boy out add me on steam http://steamcommunity.com/id/alec___/
2
#2
14 Frags +

SCAN EM
POST EM

SCAN EM
POST EM
3
#3
5 Frags +

http://puu.sh/ro05s/5016a26291.png

u like MTG big gig? ( ͡° ͜ʖ ͡°)

i never know what to do when you have to find the odds of "at least" something.
like for the mtg problem i think you have to figure the odds that you drew at least 3 land cards when doing the conditional probability because the condition would be u drew at least 3

also part c of the deck of cards problem how can you find the odds that you draw a six if the card that was removed first is unknown? i would intuitively think that since theres a 12/13 chance it wasnt a six and a 1/13 chance it was a six it would be something like: (12/13)(4/51) + (1/13)(3/51) but that just seems like some weird shit im making up because it gives me 4/52 meaning that we just ignore the fact that a card was removed entirely which seems odd

HALP

[img]http://puu.sh/ro05s/5016a26291.png[/img]
u like MTG big gig? ( ͡° ͜ʖ ͡°)

i never know what to do when you have to find the odds of "at least" something.
like for the mtg problem i think you have to figure the odds that you drew at least 3 land cards when doing the conditional probability because the condition would be u drew at least 3

also part c of the deck of cards problem how can you find the odds that you draw a six if the card that was removed first is unknown? i would intuitively think that since theres a 12/13 chance it wasnt a six and a 1/13 chance it was a six it would be something like: (12/13)(4/51) + (1/13)(3/51) but that just seems like some weird shit im making up because it gives me 4/52 meaning that we just ignore the fact that a card was removed entirely which seems odd

HALP
4
#4
0 Frags +

probably due online ggglygy

probably due online ggglygy
5
#5
8 Frags +

http://pygments.org/demo/3883283/

3.37 a = 0.00048
3.37 b = 0.4161

i don't even understand the second question why would this need to be a question

http://pygments.org/demo/3883283/

3.37 a = 0.00048
3.37 b = 0.4161

i don't even understand the second question why would this need to be a question
6
#6
2 Frags +

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